12a^2-35a-3=0

Solution for 12a^2-35a-3=0 equation:

12a^2-35a-3=0

a = 12; b = -35; c = -3;
Δ = b2-4ac
Δ = -352-4·12·(-3)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-37}{2*12}=\frac{-2}{24}
=-1/12
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+37}{2*12}=\frac{72}{24}
=3
$